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Simplifying 2c2 + 13c + 15 = 0 Reorder the terms: 15 + 13c + 2c2 = 0 Solving 15 + 13c + 2c2 = 0 Solving for variable 'c'. Factor a trinomial. (5 + c)(3 + 2c) = 0Subproblem 1
Set the factor '(5 + c)' equal to zero and attempt to solve: Simplifying 5 + c = 0 Solving 5 + c = 0 Move all terms containing c to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + c = 0 + -5 Combine like terms: 5 + -5 = 0 0 + c = 0 + -5 c = 0 + -5 Combine like terms: 0 + -5 = -5 c = -5 Simplifying c = -5Subproblem 2
Set the factor '(3 + 2c)' equal to zero and attempt to solve: Simplifying 3 + 2c = 0 Solving 3 + 2c = 0 Move all terms containing c to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + 2c = 0 + -3 Combine like terms: 3 + -3 = 0 0 + 2c = 0 + -3 2c = 0 + -3 Combine like terms: 0 + -3 = -3 2c = -3 Divide each side by '2'. c = -1.5 Simplifying c = -1.5Solution
c = {-5, -1.5}
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